来个懂点asp或者php的
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输入数字A
输入数字B
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输出X:B + (A-B)*0.9
输出C:B + (A-B)*0.6
输出D:B + (A-B)*0.5
输出E:B + (A-B)*0.2
输出D:B + (A-B)*0.1
A,B
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6楼 | miee.cn 06-29 23:27[.Net控制台C#] using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace test1 { class Program { static void Main(string[] args) { Console.WriteLine(“请输入数字A:“); int numA = Convert.ToInt32(Console.ReadLine()); Console.WriteLine(“请输入数字B:“); int numB = Convert.ToInt32(Console.ReadLine()); Console.WriteLine(“X=“+numB+(numA-numB)*0.9); Console.WriteLine(“C=“+numB+(numA-numB)*0.6); Console.WriteLine(“D=“+numB+(numA-numB)*0.5); Console.WriteLine(“E=“+numB+(numA-numB)*0.2); Console.WriteLine(“D=“+numB+(numA-numB)*0.1); Console.WriteLine(“A={0},B={1}“,numA,numB); Console.ReadLine(); } } } |
5楼 | 葬魂 06-29 23:04<% ok=Request(“ok“) If ok=1 Then A=Request(“a“) B=Request(“b“) response.write “X:“ & B + (A-B)*0.9 response.write “<br/>“ response.write “<br/>“ response.write “C:“ & B + (A-B)*0.6 response.write “<br/>“ response.write “<br/>“ response.write “D:“ & B + (A-B)*0.5 response.write “<br/>“ response.write “<br/>“ response.write “E:“ & B + (A-B)*0.2 response.write “<br/>“ response.write “<br/>“ response.write “D:“ & B + (A-B)*0.1 response.write “<br/>“ response.write “<br/>“ response.write A & “,“ & B response.write “<br/>-------------<br/>“ End If %> <form name=“ok“ action=“?ok=1“ method=“POST“> A:<input name=“a“/><br/><br/> B:<input name=“b“/><br/><br/> <input type=“submit“ value=“OK“/> |

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